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A Punnett square is a square diagram used to predict the genotypes of an offspring. The genotype is the actual genetic makeup of an organism, usually written in alleles. Humans have two alleles for every autosomal gene in our torso. A typical monohybrid cross follows one gene and can be easily observed in a 2 x 2 Punnett square. If you wanted to rails 2 genes together a 4 x iv Punnett square volition come in handy. Just, instead of filling in sixteen boxes, in that location is a quicker way to observe out the genotypes using the forked line method.

  1. 1

    Highlight clues in the problem. It is important to decipher what the problem is asking. Make sure to highlight what the dissimilar alleles produce because it tin go confusing.

  2. 2

    Write down the genotypes for both parents.

    • Heterozygous for a gene ways that ane allele is dominant and one allele is recessive.
    • Homozygous means that both alleles are either dominant or recessive.

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  3. 3

    Describe 2 2x2 Punnett squares. First, draw a large square and divide information technology into 4 equal squares. Repeat this footstep one more than time. Y'all will be crossing each gene from each parent separately. The gene for size and the gene for color will get in their own 2x2 Punnett foursquare.

  4. four

    Label the Punnet square. The mother's genotype, and the sides of the Punnett foursquare with the begetter's genotype. Remember that an individuals genotype for a dihybrid cross has 4 alleles. These 4 alleles make up two different genes.

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  1. 1

    Perform a Punnet square cross two times. Take the mother first allele write it into the two boxes beneath. Do this pace again for the mother's 2d allele. And so take the father's get-go allele and write it into the two boxes to its right. Do this step once more for the begetter'due south second allele. Once one punnet square is full do it again for the other gene. It is important to write the dominant allele first in the box when crossing the 2 alleles. "Rr" is preferred over "rR"

  2. 2

    List down the genotypes for each cross. The two letters in each box are the genotypes.

  3. iii

    Calculate how frequent each genotype shows upward in both Punnett foursquare. Answers should be written in fraction grade. The numerator for each genotype should exist somewhere from 1-iv and the denominator should be 4 for each genotype.

  4. 4

    Listing down the new three genotype frequencies yous establish from the first genetic cross (Punnett square #i). Make certain to write these numbers in a higher place one another, leaving about 2 or three inches of space between them.

  5. 5

    Draw iii arrows after each of the three frequencies. 1 arrow should point slightly upward, one horizontal, and the other slightly downwards. This is where the phrase forked line method is derived from. It should look like a fork at this betoken. A total of 9 arrows should be drawn.

  6. vi

    List downwardly the other 3 possible genotypic frequencies for the second Punnett square on each end of an pointer. There should be a total of 9 genotypic frequencies written, but they are just iii unlike frequencies.

    • Make sure this step looks the same after each of the iii separate genotypic frequencies.
  7. 7

    Draw a horizontal arrow after the genotypic frequencies you wrote downward. There should be 9 arrows.

  8. 8

    Combine the genotype from the first column and 2nd column and write them after the final arrow. Do this stride 9 times until all arrows have a 4 letter of the alphabet genotype.

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  1. i

    Write the genotypic frequency for each of the 4 letter genotype. To detect this multiply the frequency in the first column to the frequency in the 2nd cavalcade.

    • A computer can be used or just multiply the numerator separately and the denominator separately and plow it into a fraction. The denominator should be out of 16 considering (iv * 4= 16).
  2. 2

    Group the genotypic ratios of the genotypes that produce the same looking offspring. This is to notice the phenotypic ratios. There are 9 different genotypes with 4 different physical combinations possible. There should exist iv dissimilar groups of phenotypic ratios.

  3. 3

    Find the sum of the genotypic ratios that produce the same phenotype.

    • The number should exist in fraction course with the denominator of 16.
  4. iv

    Write down the phenotypic ratio in standard grade for the entire cross. The phenotypic ratios for this cantankerous are ix/16, 3/16, 3/16, ane/16. To simplify these numbers, y'all would write ix:3:three:one.

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  • If two heterozygous parents are crossing then the ratio will always be 9:3:3:one.

  • A homozygous ascendant parent crossed with a homozygous recessive parent then the all the offspring will be heterozygous.

  • These crosses just works for genes that follow independent assortment.

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